Minnie rides on a flat road at kilometers per hour (kph), downhill at kph, and uphill at kph. Penny rides on a flat road at kph, downhill at kph, and uphill at kph. Minnie goes from town to town , a distance of km all uphill, then from town to town , a distance of km all downhill, and then back to town , a distance of km on the flat. Penny goes the other way around using the same route. How many more minutes does it take Minnie to complete the -km ride than it takes Penny?
- A)
- B)
- C)
- D)
- E)
Answer
C
Key insight
Compute each leg as distance over speed; Penny rides the loop backwards, so her uphill leg is the 15 km stretch and her downhill leg is the 10 km one.
Solution
Compute each rider's time leg by leg with .
Minnie: is km uphill at kph, hours. is km downhill at kph, hour. is km flat at kph, hour. Total hours minutes.
Penny rides , so the slopes are reversed. is km flat at kph, hour minutes. is km, now uphill, at kph, hours minutes. is km, now downhill, at kph, hour minutes. Total minutes.
Difference: minutes.
The answer is .
Why this works
Multi-leg trips are handled one leg at a time, because speed changes at each leg; there is no shortcut through average speed. The one conceptual step is that a hill climbed in one direction is descended in the other, so reversing the loop reassigns the terrain to each segment.
The trap
Giving Penny the same uphill and downhill legs as Minnie; reversing direction swaps which segments are up and down.
Common mistakes
- Giving Penny the same uphill and downhill legs as Minnie; reversing direction swaps which segments are up and down.
- Mixing hours and minutes, for example adding hour as minutes.
Techniques
Set up the equation/formula and compute; no special trick needed