Two right circular cylinders have the same volume. The radius of the second cylinder is more than the radius of the first. What is the relationship between the heights of the two cylinders?
- A)
- B)
- C)
- D)
- E)
Answer
D
Key insight
Equal volumes mean r^2 h is constant; radius scaled by 1.1 scales r^2 by 1.21, so the first height equals 1.21 times the second.
Solution
Let the first cylinder have radius and height , and the second have radius and height . Equal volumes give
so . The first height is more than the second.
Note this is not the same as the second being less than the first: , a decrease of about .
The answer is
Why this works
With volume fixed, height is inversely proportional to the square of the radius. A increase in radius is a factor , and squaring gives . The remaining care is in the wording: " is more than " means , which is a different statement from " is less than ."
Alternative approach
Plug in numbers: first cylinder radius , second radius . To match volumes, ; with we get , visibly more than .
The trap
Answering that the second height is 21% less than the first; 1/1.21 is about 0.826, a 17.4% decrease, so the percent must be stated the other way.
Common mistakes
- Answering that the second height is less than the first; , a decrease, so the percent must be stated the other way.
- Forgetting to square the radius factor and choosing a relationship, choice (A) or (B).
Techniques
Set up the equation/formula and compute; no special trick needed · Test small/specific values or special cases to find or verify the answer