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2014 AMC 10A Problem 1

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2014 AMC 10A Problem 1AMC 10 Step by Step
Name:                             Date: October 28, 2026
Fractions & Decimals · difficulty 1 of 5 · about 1 min · position P1-10

What is 10⋅(12+15+110)−1?10 \cdot \left(\tfrac{1}{2} + \tfrac{1}{5} + \tfrac{1}{10}\right)^{-1}?

  1. A)33
  2. B)88
  3. C)252\frac{25}{2}
  4. D)1703\frac{170}{3}
  5. E)170170

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