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2012 AMC 10B Problem 9

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2012 AMC 10B Problem 9AMC 10 Step by Step
Name:                             Date: September 13, 2026
Number Properties · difficulty 2 of 5 · about 2 min · position P1-10

Two integers have a sum of 26. When two more integers are added to the first two integers the sum is 41. Finally when two more integers are added to the sum of the previous four integers the sum is 57. What is the minimum number of odd integers among the 6 integers?

  1. A)

    11

  2. B)

    22

  3. C)

    33

  4. D)

    44

  5. E)

    55

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