Anna enjoys dinner at a restaurant in Washington, D.C., where the sales tax on meals is 10%. She leaves a 15% tip on the price of her meal before the sales tax is added, and the tax is calculated on the pre-tip amount. She spends a total of 27.50 dollars for dinner. What is the cost of her dinner without tax or tip in dollars?
- A)
- B)
- C)
- D)
- E)
Answer
D
Key insight
The tax and the tip are both taken from the meal price, so every dollar of meal costs 1.25 dollars in total. Divide 27.50 by 1.25.
Solution
1. Read the wording carefully: the tip is on the meal price before tax, and the tax is on the meal price before tip. So both are percents of the same number, the meal price.
2. See what one dollar of meal costs in total. It is dollar for the meal, plus tax, plus tip, which is dollars.
3. So the total bill is times the meal price. Call the meal price :
4. Divide to undo the multiplying: .
5. Check: tax is of , which is . Tip is of , which is . Then . Correct.
The answer is .
Why this works
When several percents are all taken of the same starting amount, you can add them into one multiplier (here ). To go backward from a total to the starting amount, divide by that multiplier. Subtracting of the total gives the wrong answer, because the was taken of the smaller meal price, not of the total.
Alternative approach
Try the answer choices. Each total is the choice times :
| Meal | |||||
|---|---|---|---|---|---|
| Total |
Only gives .
The trap
Taking 25% off the total 27.50 (which gives about 20.63) instead of dividing by 1.25, or adding the tip on top of the tax.
Concise solution
Let the meal cost dollars. The tax is of and the tip is of ; both are computed on the same pre-tax, pre-tip price. So the total is
Dividing, .
Check: .
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Algebra, Chapter 3: One-Variable Linear Equations (§3.3, §3.4)
- Introduction to Algebra, Chapter 7: Proportion (§7.1, §7.2, §7.3)
- Prealgebra, Chapter 13: Data and Statistics (§13.1)
Techniques
Set up the equation/formula and compute; no special trick needed