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2012 AMC 10B Problem 2

2012 AMC 10B Problem 2AMC 10 Step by Step

Name: Date: October 28, 2026

Quadrilaterals & Polygon Areas · difficulty 1 of 5 · about 1 min · position P1-10

A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to its width is 2:1. What is the area of the rectangle?

A) $50$
B) $100$
C) $125$
D) $150$
E) $200$

Answer

Key insight

The circle touches the top and bottom of the rectangle, so the width equals the circle's diameter, 10. The length is twice that, 20.

Solution

The circle fits snugly inside the rectangle, touching the top side and the bottom side. So the distance from top to bottom (the width) is the distance straight across the circle, which is the diameter.
The radius is $5$ , so the diameter is $2 \times 5 = 10$ . The width is $10$ .
The length is twice the width: $2 \times 10 = 20$ .
The area is length times width: $20 \times 10 = 200$ .

The answer is $\boxed{\textbf{(E)}\ 200}$ .

Why this works

When a circle touches two parallel sides, those sides are exactly one diameter apart. Whenever a problem gives a radius and asks about side lengths, turn the radius into a diameter first. After that, the ratio $2:1$ gives the other side right away.

The trap

Using the radius 5 as the width instead of the diameter 10, which gives a rectangle 5 by 10 and the wrong area 50.

Concise solution

The circle is tangent to the top and bottom sides of the rectangle, so the distance between those sides, the width, equals the circle's diameter: $2 \cdot 5 = 10$ .

The length is twice the width, so it is $20$ . The area is
$20 \cdot 10 = 200.$

The answer is $\boxed{\textbf{(E)}\ 200}$ .

Review in the AoPS books

Introduction to Geometry, Chapter 8: Quadrilaterals
Introduction to Geometry, Chapter 11: Circles
Introduction to Geometry, Chapter 9: Polygons (§9.3)
Introduction to Geometry, Chapter 12: Circles and Angles

Techniques

Set up the equation/formula and compute; no special trick needed