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2011 AMC 10B Problem 18

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2011 AMC 10B Problem 18AMC 10 Step by Step
Name:                             Date: September 13, 2026
Triangles: Area & Pythagorean · difficulty 3 of 5 · about 4 min · position P16-20

Rectangle ABCDABCD has AB=6AB = 6 and BC=3BC = 3 . Point MM is chosen on side ABAB so that ∠AMD=∠CMD\angle AMD = \angle CMD . What is the degree measure of ∠AMD\angle AMD ?

  1. A)

    1515

  2. B)

    3030

  3. C)

    4545

  4. D)

    6060

  5. E)

    7575

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