Every high school in the city of Euclid sent a team of students to a math contest. Each participant in the contest received a different score. Andrea's score was the median among all students, and hers was the highest score on her team. Andrea's teammates Beth and Carla placed th and th, respectively. How many schools are in the city?
- A)
- B)
- C)
- D)
- E)
Answer
B
Key insight
With 3n students Andrea's median rank is (3n+1)/2, so n is odd; she is above 37th, so n < 25, and 64 students exist, so n >= 22.
Solution
Let there be schools, so students with distinct scores. Andrea is the median, so she is a single middle student; that requires to be odd, i.e. odd, and her rank is .
Andrea outscored Beth, who is th, so
Carla is th, so there are at least students: , giving .
The only odd integer in is . Check: students, Andrea is th, above Beth's th, and Carla's th place exists.
The answer is .
Why this works
Every sentence becomes an inequality on : the median's rank gives an upper bound, the existence of a th place gives a lower bound, and parity (the median of distinct scores is an actual person only when the count is odd) selects the unique value. Squeeze from both sides, then apply the integrality condition.
The trap
Forgetting that a median of an even number of distinct scores is not a participant, which forces n to be odd.
Common mistakes
- Forgetting that a median of an even number of distinct scores is not a participant, which forces n to be odd.
- Using only the upper bound and picking or , or misreading "highest on her team" and allowing Andrea to be below th.
Techniques
Bound the quantity above/below or estimate to pin it down · Use an invariant, parity, or coloring argument