AMC 10 Step by Step

2010 AMC 10A Problem 5

P1-10~1 minPrint

The area of a circle whose circumference is 24π24\pi is kπk\pi . What is the value of kk ?

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Key insight

Go through the radius: the circumference 2 times pi times r equals 24 pi, so r = 12, and the area is pi times 12 squared = 144 pi.

Solution

Both the circumference and the area are built from the radius, so find the radius first.

  1. The circumference of a circle with radius rr is 2πr2\pi r.
  2. We are told it is 24π24\pi, so 2πr=24π2\pi r = 24\pi. Divide both sides by 2π2\pi: r=12r = 12.
  3. The area is πr2=π×12×12=144π\pi r^2 = \pi \times 12 \times 12 = 144\pi.
  4. The area is written as kπk\pi, so k=144k = 144.

The answer is (E) 144\boxed{\textbf{(E)}\ 144}.

Why this works

For circles, the radius is the key that connects everything: diameter, circumference and area. Turn whatever you are given into the radius, then turn the radius into what is asked. Leaving π\pi as a symbol saves you from any decimals.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

The circumference of a circle of radius rr is 2πr2\pi r. Setting 2πr=24π2\pi r = 24\pi gives r=12r = 12.

The area is then
πr2=π⋅122=144π,\pi r^2 = \pi \cdot 12^2 = 144\pi,
so k=144k = 144.

The answer is (E) 144\boxed{\textbf{(E)}\ 144}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.