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2010 AMC 10A Problem 13

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2010 AMC 10A Problem 13AMC 10 Step by Step
Name:                             Date: September 13, 2026
Linear Equations & Word Problems · difficulty 2 of 5 · about 2 min · position P11-15

Angelina drove at an average rate of 8080 km/h and then stopped 2020 minutes for gas. After the stop, she drove at an average rate of 100100 km/h. Altogether she drove 250250 km in a total trip time of 33 hours including the stop. Which equation could be used to solve for the time tt in hours that she drove before her stop?

  1. A)

    80t+100(83−t)=25080t + 100\left(\frac{8}{3} -t\right) = 250

  2. B)

    80t=25080t = 250

  3. C)

    100t=250100t = 250

  4. D)

    90t=25090t = 250

  5. E)

    80(83−t)+100t=25080\left(\frac{8}{3} -t\right) + 100t = 250

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