Yesterday Han drove 1 hour longer than Ian at an average speed 5 miles per hour faster than Ian. Jan drove 2 hours longer than Ian at an average speed 10 miles per hour faster than Ian. Han drove 70 miles more than Ian. How many more miles did Jan drive than Ian?
- A)
- B)
- C)
- D)
- E)
Answer
D
Key insight
Expanding Han's distance gives v + 5t = 65 for Ian's speed v and time t; Jan's excess 2v + 10t + 20 is exactly twice that plus 20.
Solution
Let Ian drive for hours at miles per hour, covering miles.
Han drove miles, which is more than Ian's :
Jan drove miles, so Jan's excess over Ian is
The answer is .
Why this works
The problem looks under-determined (two unknowns, one equation), but the quantity asked for is a linear combination of the same expression the given data determines. Expand both products, cancel the common , and compare the leftover linear parts. This "you do not need the individual values" pattern is common on the AMC.
Alternative approach
Any pair with works, so take , : Ian miles, Han (check: more), Jan , which is more than Ian.
The trap
Trying to solve for v and t individually; there is only one equation, but the target expression depends only on the combination v + 5t.
Common mistakes
- Trying to solve for v and t individually; there is only one equation, but the target expression depends only on the combination v + 5t.
- Guessing "twice 70" because Jan's increases are double Han's, forgetting the extra cross term .
Techniques
Set up the equation/formula and compute; no special trick needed · Test small/specific values or special cases to find or verify the answer