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2007 AMC 10A Problem 2

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2007 AMC 10A Problem 2AMC 10 Step by Step
Name:                             Date: October 28, 2026
Functions · difficulty 1 of 5 · about 1 min · position P1-10

Define a@b=ab−b2a@b = ab - b^{2} and a#b=a+b−ab2a\#b = a + b - ab^{2} . What is 6@26#2\frac {6@2}{6\#2} ?

  1. A)−12- \frac {1}{2}
  2. B)−14- \frac {1}{4}
  3. C)18\frac {1}{8}
  4. D)14\frac {1}{4}
  5. E)12\frac {1}{2}

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