Doug and Dave shared a pizza with equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was dollars, and there was an additional cost of dollars for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?
- A)
- B)
- C)
- D)
- E)
Answer
D
Key insight
Give each slice its own price: every slice costs 1 dollar, and the 2-dollar anchovy charge is shared only by the 4 anchovy slices.
Solution
"Each paid for what he had eaten," so first find the price of each slice.
- Plain part. The plain pizza costs dollars for slices, so every slice carries dollar.
- Anchovy part. The extra dollars is only for the anchovy half, the anchovy slices. So those slices together cost dollars.
- Dave ate the anchovy slices ( dollars) and plain slice ( dollar). He pays dollars.
- Doug ate the other plain slices. He pays dollars.
- Check: , which is the whole bill, . Good.
Dave paid dollars more.
The answer is .
Why this works
When people pay for what they eat, attach every cost to the slice it belongs to, including extra charges for toppings. Then each person's bill is just the sum of his slices. Checking that the two bills add up to the total catches most mistakes.
Alternative approach
Start from the total. The whole bill is dollars. Doug ate only plain slices, of them at dollar each, so he pays . Dave pays the rest, . The difference is .
The trap
Spreading the 2-dollar anchovy charge over all 8 slices, or splitting it between Dave and Doug, even though only Dave ate anchovies.
Concise solution
The plain pizza is dollars for slices, so each slice carries dollar of base cost. The -dollar anchovy charge belongs entirely to the four anchovy slices.
Dave ate the four anchovy slices, worth dollars, plus one plain slice worth dollar: he pays dollars.
Doug ate the other three plain slices: dollars.
Check: , the whole bill. The difference is .
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 3: One-Variable Linear Equations (§3.3, §3.4)
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Algebra, Chapter 7: Proportion (§7.4)
- Prealgebra, Chapter 13: Data and Statistics (§13.1)
Techniques
Set up the equation/formula and compute; no special trick needed