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2004 AMC 10B Problem 24

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2004 AMC 10B Problem 24AMC 10 Step by Step
Name:                             Date: September 13, 2026
Circles · difficulty 4 of 5 · about 5 min · position P21-25

In triangle ABCABC we have AB=7AB=7 , AC=8AC=8 , BC=9BC=9 . Point DD is on the circumscribed circle of the triangle so that ADAD bisects angle BACBAC . What is the value of ADCD\frac{AD}{CD} ?

  1. A)

    98\dfrac{9}{8}

  2. B)

    53\dfrac{5}{3}

  3. C)

    22

  4. D)

    177\dfrac{17}{7}

  5. E)

    52\dfrac{5}{2}

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