A bag initially contains red marbles and blue marbles only, with more blue than red. Red marbles are added to the bag until only of the marbles in the bag are blue. Then yellow marbles are added to the bag until only of the marbles in the bag are blue. Finally, the number of blue marbles in the bag is doubled. What fraction of the marbles now in the bag are blue?
- A)
- B)
- C)
- D)
- E)
Answer
C
Key insight
Only the last snapshot matters: blue is 1/5 of the bag, so blue : other = 1 : 4, and doubling blue makes it 2 : 4, i.e. one third.
Solution
The red and yellow steps only set the stage; what matters is the bag just before the last step, when blue marbles are of the total. Write that as blue marbles and non-blue marbles.
Doubling the blue marbles gives blue, while the others are untouched. The bag now holds marbles, of which
are blue.
The answer is .
Why this works
A fraction of the whole is a part-to-whole ratio; to see the effect of changing one part, convert to a part-to-part ratio (blue : other ), change the part, and convert back. The earlier steps are a distraction: multi-stage word problems often only need the final state.
Alternative approach
Use concrete numbers. Start with blue and red; add red so blue is of (one third); add yellow so blue is of (one fifth); double blue to of , which is .
The trap
Doubling the fraction 1/5 to 2/5 (choice (D)), forgetting that the added blue marbles also enlarge the total.
Common mistakes
- Doubling the fraction 1/5 to 2/5 (choice (D)), forgetting that the added blue marbles also enlarge the total.
- Getting tangled in the red and yellow stages and trying to track all four colors symbolically when only the final ratio is needed.
Techniques
Set up the equation/formula and compute; no special trick needed · Test small/specific values or special cases to find or verify the answer