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2003 AMC 10B Problem 3

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2003 AMC 10B Problem 3AMC 10 Step by Step
Name:                             Date: September 13, 2026
Sequences & Series · difficulty 1 of 5 · about 2 min · position P1-10

The sum of 55 consecutive even integers is 44 less than the sum of the first 88 consecutive odd counting numbers. What is the smallest of the even integers?

  1. A)

    66

  2. B)

    88

  3. C)

    1010

  4. D)

    1212

  5. E)

    1414

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