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2003 AMC 10B Problem 14

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2003 AMC 10B Problem 14AMC 10 Step by Step
Name:                             Date: September 13, 2026
Exponents, Logarithms & Radicals · difficulty 2 of 5 · about 2 min · position P11-15

Given that 38⋅52=ab,3^8\cdot5^2=a^b, where both aa and bb are positive integers, find the smallest possible value for a+ba+b .

  1. A)

    2525

  2. B)

    3434

  3. C)

    351351

  4. D)

    407407

  5. E)

    900900

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