Al, Betty, and Clare split among them to be invested in different ways. Each begins with a different amount. At the end of one year, they have a total of dollars. Betty and Clare have both doubled their money, whereas Al has managed to lose dollars. What was Al's original portion?
- A)
$250
- B)
$350
- C)
$400
- D)
$450
- E)
$500
Answer
C
Key insight
Betty and Clare only matter as a combined sum (1000 - a) that doubles; the total 1500 then forces a = 400.
Solution
Let Al start with dollars. Betty and Clare together start with dollars. Since each of them doubles her money, together they end with , while Al ends with .
The final total is :
Check: Betty and Clare start with and end with ; Al ends with ; .
The answer is .
Why this works
Betty and Clare undergo the same transformation (doubling), so their individual amounts never need to be separated; only their sum enters the equations. Collapsing them into one variable turns a three-unknown system into a single linear equation. The phrase "each begins with a different amount" is irrelevant to the answer.
Alternative approach
Had Al not lost , the final total would be , a gain of over the initial . All of that gain came from Betty and Clare doubling, so they started with and Al with .
The trap
Trying to determine Betty's and Clare's individual amounts (impossible) instead of treating their combined money as one quantity.
Common mistakes
- Trying to determine Betty's and Clare's individual amounts (impossible) instead of treating their combined money as one quantity.
- Writing Al's final amount as or as but then doubling it along with the others.
Techniques
Set up the equation/formula and compute; no special trick needed