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2003 AMC 10A Problem 5

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2003 AMC 10A Problem 5AMC 10 Step by Step
Name:                             Date: September 13, 2026
Quadratics · difficulty 1 of 5 · about 1 min · position P1-10

Let dd and ee denote the solutions of 2x2+3x−5=02x^{2}+3x-5=0 . What is the value of (d−1)(e−1)(d-1)(e-1) ?

  1. A)

    −52-\frac{5}{2}

  2. B)

    00

  3. C)

    33

  4. D)

    55

  5. E)

    66

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