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2002 AMC 10A Problem 3

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2002 AMC 10A Problem 3AMC 10 Step by Step
Name:                             Date: September 13, 2026
Exponents, Logarithms & Radicals · difficulty 2 of 5 · about 3 min · position P1-10

According to the standard convention for exponentiation, 2222=2(2(22))=216=65536.2^{2^{2^{2}}} = 2^{(2^{(2^2)})} = 2^{16} = 65536.

If the order in which the exponentiations are performed is changed, how many other values are possible?

  1. A)

    00

  2. B)

    11

  3. C)

    22

  4. D)

    33

  5. E)

    44

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