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2000 AMC 10 Problem 9

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2000 AMC 10 Problem 9AMC 10 Step by Step
Name:                             Date: September 13, 2026
Absolute Value & Inequalities · difficulty 1 of 5 · about 1 min · position P1-10

If ∣x−2∣=p|x - 2| = p , where x<2x < 2 , then x−p=x - p =

  1. A)

    −2-2

  2. B)

    22

  3. C)

    2−2p2-2p

  4. D)

    2p−22p-2

  5. E)

    ∣2p−2∣|2p-2|

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