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2000 AMC 10 Problem 9
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2000 AMC 10 Problem 9
AMC 10 Step by Step
Name:
Date: October 28, 2026
Absolute Value & Inequalities · difficulty 1 of 5 · about 1 min · position P1-10
If
∣
x
−
2
∣
=
p
|x - 2| = p
∣
x
−
2∣
=
p
, where
x
<
2
x < 2
x
<
2
, then
x
−
p
=
x - p =
x
−
p
=
A)
−
2
-2
−
2
B)
2
2
2
C)
2
−
2
p
2-2p
2
−
2
p
D)
2
p
−
2
2p-2
2
p
−
2
E)
∣
2
p
−
2
∣
|2p-2|
∣2
p
−
2∣
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