AMC 10 Step by Step

2000 AMC 10 Problem 2

P1-10~1 minPrint

2000(20002000)=x2000(2000^{2000}) = x Find x.

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Key insight

2000 is the same as 2000 to the first power. Multiplying one more 2000 onto 2000 copies of 2000 gives 2001 copies.

Solution

1. Remember what an exponent means: 200020002000^{2000} is 20002000 copies of the number 20002000 multiplied together.
2. The problem multiplies this by one more 20002000.
3. So now there are 2000+1=20012000 + 1 = 2001 copies of 20002000 multiplied together, which is 200020012000^{2001}.
4. The same thing written with the exponent rule: 2000=200012000 = 2000^1, and when you multiply powers of the same number you add the exponents:
20001⋅20002000=20002001.2000^{1} \cdot 2000^{2000} = 2000^{2001}.

The answer is (A) 20002001\boxed{\textbf{(A)}\ 2000^{2001}}.

Why this works

An exponent just counts how many copies are being multiplied. Adding one more copy raises the count by one. You never multiply the bases (that would give 40004000) or multiply the exponents (that only happens for a power of a power, like (a2)3(a^2)^3).

Alternative approach

Try the same thing with small numbers where you can check by hand. 2⋅23=2⋅8=162 \cdot 2^3 = 2 \cdot 8 = 16, and 24=162^4 = 16. The wrong patterns give 43=644^3 = 64 or 26=642^6 = 64, which do not match. The pattern that works is "raise the exponent by one," which is choice (A).

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Write the leading 20002000 as 200012000^1. Both factors now share the base 20002000, and powers of the same base multiply by adding exponents:
20001⋅20002000=20001+2000=20002001.2000^{1} \cdot 2000^{2000} = 2000^{1 + 2000} = 2000^{2001}.

The answer is (A) 20002001\boxed{\textbf{(A)}\ 2000^{2001}}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site. Also appeared as 2000 12 #2.